Subnetting Question 6
You have a network ID of 192.168.10.0 and require at least 25 hosts for each subnet, with the largest amount of subnets available. Which subnet mask should you assign?
A. | 255.255.255.192 |
B. | 255.255.255.224 |
C. | 255.255.255.240 |
D. | 255.255.255.248 |
E. | 255.255.255.255 |
Solution
Hence, 192.168.10.0 is a class C IP Address and by default, its network bit is 24 and host bit is 8.
A/Q, we need a minimum of 25 hosts with maximum subnets.
So, we have to reserve 5 bits for the host from the last octet (25 = 32). This is the number of host closest to 25 and the remaining 3 bits are the network bits.
(11111111.11111111.11111111.11100000)
(27 + 26 + 25 + 24 + 23 + 22 + 21 + 20) . (27 + 26 + 25 + 24 + 23 + 22 + 21 + 20) . (27 + 26 + 25 + 24 + 23 + 22 + 21 + 20) . (27 + 26 + 25 )
So, the subnet mask is 255.255.255.224
Here is a video tutorial of this subnetting question.
SUBNETTING QUESTION 6 | Find the subnet mask for minimum 25 Host with maximum subnets