Subnetting Question 3
On a class B network, how many hosts are available at each site with a subnet mask of 248?
- 16,382
- 8,190
- 4,094
- 2,046
Solution
Hence the subnet mask is 255.255.248.0
It means, 5 bits are borrowed from the third block to make it 248 (27 + 26 + 25 +24 + 23 = 248)
Now, let’s count the number of hosts
So the remaining host bits in the third and fourth block is 3 + 8 = 11.
The formula for counting the number of hosts is
2n – 2 (where n indicates the number of host bits and subtracted 2 because the first IP address is reserved for the network id and the last IP address is reserved for the broadcast ID and this two address cannot use in the host)
211 – 2 = 2046
So the answer is 2046 hosts are available with the subnet mask of 255.255.248.0
Here is a video tutorial of this Subnetting Question 3
Class B Subnetting Video Tutorial
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