Subnetting Questions 29
Enter the broadcast address for the network 10.138.186.0/24
Hence, the IP Address starts from 10 it indicates it is a Class A Network. By default, in Class A network 8 bits are reserved for the network and 24 bits are reserved for the host.
A/Q the CIDR value is /24. So we have to borrow another 16 bits (8 + 16 = 24)
11111111.11111111.11111100.00000000
So, its Subnet Mask is 255.255.255.0
Let’s count the number of subnets
2n (Here, n indicates the total number of network bits borrowed)
216 = 65536 Subnets are available.
Let’s count the number of IP Address on each network
2n (Here, n indicates the total number of host bits)
28 = 256 IP Address is available on each network
List of top 5 subnets (Network)
| Network ID | First host | Last host | Subnet mask | Broadcast |
| 10.138.186.0 | 10.138.186.1 | 10.138.186.254 | 255.255.255.0 | 10.138.186.255 |
| 10.138.187.0 | 10.138.187.1 | 10.138.187.254 | 255.255.255.0 | 10.138.187.255 |
| 10.138.188.0 | 10.138.188.1 | 10.138.188.254 | 255.255.255.0 | 10.138.188.255 |
| 10.138.189.0 | 10.138.189.1 | 10.138.189.254 | 255.255.255.0 | 10.138.189.255 |
| 10.138.190.0 | 10.138.190.1 | 10.138.190.254 | 255.255.255.0 | 10.138.190.255 |
So, our first broadcast ID is 10.138.186.255
Class A Subnetting Video Tutorial
CLASS A SUBNETTING with Example | How to do Subnetting for class A IP Address & Subnetting Quiz
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