Subnetting Questions 27
Enter the first valid host on the network that the host 10.253.144.108/22 is a part of
Solution
Hence, the IP Address starts from 10 it indicates it is a Class A Network. By default, in Class A network 8 bits are reserved for the network and 24 bits are reserved for the host.
A/Q the CIDR value is /22. So we have to borrow another 14 bits (8 + 14 = 22)
11111111.11111111.11111100.00000000
So, its Subnet Mask is 255.255.252.0
Let’s count the number of subnets
2n (Here, n indicates the total number of network bits borrowed)
214 = 16384 Subnets are available.
Let’s count the number of IP Address on each network
2n (Here, n indicates the total number of host bits)
210 = 1024 IP Address is available on each network
List of top 5 subnets (Network)
Network ID | 1st Host | Last Host | Subnet Mask | Broadcast Address |
10.253.144.0 | 10.253.144.1 | 10.253.147.254 | 255.255.252.0 | 10.253.147.255 |
10.253.148.0 | 10.253.148.1 | 10.253.151.254 | 255.255.252.0 | 10.253.151.255 |
10.253.152.0 | 10.253.152.1 | 10.253.155.254 | 255.255.252.0 | 10.253.155.255 |
10.253.156.0 | 10.253.156.1 | 10.253.159.254 | 255.255.252.0 | 10.253.159.255 |
10.253.160.0 | 10.253.160.1 | 10.253.163.254 | 255.255.252.0 | 10.253.163.255 |
Hence, the IP Address 10.253.144.108 falls under the first network (10.253.144.0).
Therefore, 10.253.144.1 is the first valid host.
Class A Subnetting Tutorial
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